Recipe Conversion

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Bowhunter
Light Lager
Light Lager
Posts: 19
Joined: Sat Dec 28, 2002 10:47 am
Location: Dousman, WI, US

Recipe Conversion

Post by Bowhunter »

Hi Fellow Brewers

I found a partial mash recipe that I would like to convert to all grain. What is the formula to convert a given number of pounds of extract to an equal amount of grains ?
BillyBock
Imperial Stout
Imperial Stout
Posts: 561
Joined: Sun Dec 31, 2000 11:37 am
Location: Ohio

This Will Get You in the Ballpark

Post by BillyBock »

The exact answer will depend on your system's extraction efficiency. For syrup extract, an estimate based on 70% mash efficiency is:

(pounds extract) * 1.33 = pounds grain

For dry extract it'd be:

(pounds extract) * 1.63 = pounds grain

The numbers are based on the potential yields. For syrup it's 36 ppppg (points/pound/gallon). For dry it's 44 ppppg. For grain it's 38 ppppg (at 100% efficiency). At 70% efficiency, your grain yield is about 27 ppppg (38 * 0.7 = 26.6). All you have to do is determine the ratios and you're set. From the syrup example, the ratio is the syrup yield to the grain yield (36/27=1.33). If you have a different extraction efficiency, just recompute the grain yield and then redetermine the ratio. At 80%, your grain yield is (38 * 0.8 = 30) and your conversion ratio would be (36/30=1.2).

Hope this helps, have at it and brew on!

v/r
Bill
Bowhunter
Light Lager
Light Lager
Posts: 19
Joined: Sat Dec 28, 2002 10:47 am
Location: Dousman, WI, US

BillyBock

Post by Bowhunter »

Thanks for your help Bill
Tom
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